[BOJ 17624] DVOfficer #9
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Link
(문제에 대한 링크)
Topic
DP, TREE DP
Approach
For Each Tree node, You can find if (i,j) : (TreeSize i, BlackStone Count j) is available by dp on dfs. this method can cause time limit.
Because each table have continus value range, you don't have to find all value is availible. you can just find for BlackStone j and root node n, possible maximun Tree Size and minimum treeSize.
Then For each query, if Tree Size of query is between tree size max~min of black stone cnt of query, result is 1, else 0.
Note
(남길말)
Who the hell come up with that combination of tree and dp :(