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题目描述

请实现一个函数,把字符串 s 中的每个空格替换成"%20"。

示例 1:

输入:s = "We are happy."
输出:"We%20are%20happy."

限制:

  • 0 <= s 的长度 <= 10000

解法

  • 使用 replace() 替换。
  • 遍历添加。

Python3

class Solution:
    def replaceSpace(self, s: str) -> str:
        return s.replace(' ', '%20')

Java

  • 使用 replace:
class Solution {
    public String replaceSpace(String s) {
        return s.replaceAll(" ", "%20");
    }
}
  • 使用 StringBuilder:
class Solution {
    public String replaceSpace(String s) {
        StringBuilder sb = new StringBuilder();
        char[] chars = s.toCharArray();
        for (char c : chars) {
            sb.append(c == ' ' ? "%20" : c);
        }
        return sb.toString();
    }
}

JavaScript

  • 使用字符串内置方法
/**
 * @param {string} s
 * @return {string}
 */
var replaceSpace = function (s) {
    return s.split(" ").join("%20");
};
  • 双指针
/**
 * @param {string}
 * @return {string}
 */
var replaceSpace = function (s) {
    s = s.split("");
    let emptyNum = 0;
    for (let i = 0; i < s.length; i++) {
        if (s[i] === " ") {
            emptyNum++;
        }
    }
    let p1 = s.length - 1;
    let p2 = p1 + 2 * emptyNum;
    while (p1 >= 0 && p2 > p1) {
        if (s[p1] === " ") {
            s[p2] = "0";
            s[--p2] = "2";
            s[--p2] = "%";
        } else {
            s[p2] = s[p1];
        }
        p1--;
        p2--;
    }
    return s.join("");
};

Go

func replaceSpace(s string) string {
    return strings.Replace(s, " ", "%20", -1 )
}

C++

class Solution {
public:
    string replaceSpace(string s) {
        string ans;
        for (char ch : s) {
            if (ch == ' ')
                ans += "%20";
            else
                ans += ch;
        }
        return ans;
    }
};

TypeScript

  • 使用 replace()
function replaceSpace(s: string): string {
    return s.replace(/\s/g, "%20");
}
  • 遍历添加
function replaceSpace(s: string): string {
    const strArr = [];
    for (const c of s) {
        strArr.push(c === " " ? "%20" : c);
    }
    return strArr.join("");
}

Rust

  • 使用 replace()
impl Solution {
    pub fn replace_space(s: String) -> String {
        s.replace(' ', "%20")
    }
}
  • 遍历添加
impl Solution {
    pub fn replace_space(s: String) -> String {
        let mut result = String::new();
        for c in s.chars() {
            if c == ' ' {
                result.push_str("%20");
            } else {
                result.push(c);
            }
        }
        result
    }
}

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