Given two integer arrays of equal length target
and arr
.
In one step, you can select any non-empty sub-array of arr
and reverse it. You are allowed to make any number of steps.
Return True if you can make arr
equal to target
, or False otherwise.
Input: target = [1,2,3,4], arr = [2,4,1,3] Output: true Explanation: You can follow the next steps to convert arr to target: 1- Reverse sub-array [2,4,1], arr becomes [1,4,2,3] 2- Reverse sub-array [4,2], arr becomes [1,2,4,3] 3- Reverse sub-array [4,3], arr becomes [1,2,3,4] There are multiple ways to convert arr to target, this is not the only way to do so.
Input: target = [7], arr = [7] Output: true Explanation: arr is equal to target without any reverses.
Input: target = [1,12], arr = [12,1] Output: true
Input: target = [3,7,9], arr = [3,7,11] Output: false Explanation: arr doesn't have value 9 and it can never be converted to target.
Input: target = [1,1,1,1,1], arr = [1,1,1,1,1] Output: true
target.length == arr.length
1 <= target.length <= 1000
1 <= target[i] <= 1000
1 <= arr[i] <= 1000
impl Solution {
pub fn can_be_equal(target: Vec<i32>, arr: Vec<i32>) -> bool {
let mut target = target;
let mut arr = arr;
target.sort_unstable();
arr.sort_unstable();
target == arr
}
}